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Compare American Fork to Midvale
This post compares American Fork, Utah to Midvale, Utah across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | American Fork (city) | Midvale (city) |
|---|---|---|
| Population | 28,507 | 32,249 |
| Income (median) | $47,318 | $40,136 |
| Home Value (median) | $243,700 | $216,600 |
| White | 92% | 79% |
| Black | 0% | 3% |
| Asian | 0% | 3% |
| With Kids | 50% | 33% |
| Age (median) | 27 | 30 |
| Rentals | 24% | 58% |
Questions and Answers:
Q: Which is more populated, American Fork or Midvale?
A: American Fork has a similar population count than Midvale: 28507 compared with 32249 total people.
Q: Do incomes tend to be higher in American Fork or in Midvale?
A: Incomes are on average higher in American Fork.
Q: Are homes more expensive in American Fork or Midvale?
A: Homes tend to be similarly priced in American Fork.
Q: Which has a higher percentage of housing rental units?
A: Midvale does. The percentage of rentals differs quite a bit: 24% for American Fork versus 58% for Midvale.
Somewhat similar in-state cities, towns, and CDPs to American Fork may include: Spanish-Fork, Springville, and Pleasant-Grove.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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