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Compare Cedar Park to Rosenberg
This post compares Cedar Park, Texas to Rosenberg, Texas across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Cedar Park (city) | Rosenberg (city) |
|---|---|---|
| Population | 70,010 | 35,867 |
| Income (median) | $61,636 | $38,040 |
| Home Value (median) | $258,200 | $132,600 |
| White | 80% | 72% |
| Black | 3% | 15% |
| Asian | 9% | 2% |
| With Kids | 46% | 42% |
| Age (median) | 35 | 32 |
| Rentals | 29% | 46% |
Questions and Answers:
Q: Which is more populated, Cedar Park or Rosenberg?
A: Cedar Park has a larger population count than Rosenberg: 70010 compared with 35867 total people.
Q: Do incomes tend to be higher in Cedar Park or in Rosenberg?
A: Incomes are on average much higher in Cedar Park.
Q: Are homes more expensive in Cedar Park or Rosenberg?
A: Homes tend to be more expensive in Cedar Park.
Q: Which has a higher percentage of housing rental units?
A: Rosenberg does. The percentage of rentals differs quite a bit: 29% for Cedar Park versus 46% for Rosenberg.
Somewhat similar in-state cities, towns, and CDPs to Cedar Park may include: McKinney, League-City, and Brushy-Creek.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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