Compare-Cities.com
Compare Sanford to Jacksonville
This post compares Sanford, North Carolina to Jacksonville, North Carolina across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
Dimension | Sanford (city) | Jacksonville (city) |
---|---|---|
Population | 29,051 | 73,661 |
Income (median) | $35,673 | $26,418 |
Home Value (median) | $137,400 | $153,400 |
White | 62% | 67% |
Black | 26% | 18% |
Asian | 1% | 3% |
With Kids | 35% | 40% |
Age (median) | 34 | 23 |
Rentals | 46% | 67% |
Questions and Answers:
Q: Which is more populated, Sanford or Jacksonville?
A: Sanford has a much smaller population count than Jacksonville: 29051 compared with 73661 total people.
Q: Do incomes tend to be higher in Sanford or in Jacksonville?
A: Incomes are on average much higher in Sanford.
Q: Are homes more expensive in Sanford or Jacksonville?
A: Homes tend to be similarly priced in Sanford.
Q: Which has a higher percentage of housing rental units?
A: Jacksonville does. The percentage of rentals differs quite a bit: 46% for Sanford versus 67% for Jacksonville.
Somewhat similar in-state cities, towns, and CDPs to Sanford may include: Kannapolis, Gastonia, and Monroe.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
City first letter menu:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z