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Compare Sarasota to Jacksonville Beach
This post compares Sarasota, Florida to Jacksonville Beach, Florida across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Sarasota (city) | Jacksonville Beach (city) |
|---|---|---|
| Population | 55,103 | 22,833 |
| Income (median) | $35,434 | $57,776 |
| Home Value (median) | $215,100 | $317,000 |
| White | 81% | 91% |
| Black | 13% | 2% |
| Asian | 1% | 2% |
| With Kids | 17% | 19% |
| Age (median) | 47 | 42 |
| Rentals | 44% | 33% |
Questions and Answers:
Q: Which is more populated, Sarasota or Jacksonville Beach?
A: Sarasota has a larger population count than Jacksonville Beach: 55103 compared with 22833 total people.
Q: Do incomes tend to be higher in Sarasota or in Jacksonville Beach?
A: Incomes are on average much lower in Sarasota.
Q: Are homes more expensive in Sarasota or Jacksonville Beach?
A: Homes tend to be less expensive in Sarasota.
Q: Which has a higher percentage of housing rental units?
A: Sarasota does. The percentage of rentals differs quite a bit: 44% for Sarasota versus 33% for Jacksonville Beach.
Somewhat similar in-state cities, towns, and CDPs to Sarasota may include: Hallandale-Beach, Clearwater, and Bradenton.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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