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Compare Ormond Beach to Sanford
This post compares Ormond Beach, Florida to Sanford, Florida across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Ormond Beach (city) | Sanford (city) |
|---|---|---|
| Population | 41,238 | 57,979 |
| Income (median) | $42,391 | $36,585 |
| Home Value (median) | $176,900 | $113,100 |
| White | 88% | 60% |
| Black | 3% | 26% |
| Asian | 3% | 3% |
| With Kids | 20% | 31% |
| Age (median) | 51 | 33 |
| Rentals | 26% | 47% |
Questions and Answers:
Q: Which is more populated, Ormond Beach or Sanford?
A: Ormond Beach has a smaller population count than Sanford: 41238 compared with 57979 total people.
Q: Do incomes tend to be higher in Ormond Beach or in Sanford?
A: Incomes are on average higher in Ormond Beach.
Q: Are homes more expensive in Ormond Beach or Sanford?
A: Homes tend to be more expensive in Ormond Beach.
Q: Which has a higher percentage of housing rental units?
A: Sanford does. The percentage of rentals differs quite a bit: 26% for Ormond Beach versus 47% for Sanford.
Somewhat similar in-state cities, towns, and CDPs to Ormond Beach may include: Vero-Beach-South, Palm-Harbor, and Merritt-Island.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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