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Compare Lake Worth to Bloomingdale
This post compares Lake Worth, Florida to Bloomingdale, Florida across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Lake Worth (city) | Bloomingdale (CDP) |
|---|---|---|
| Population | 37,354 | 23,395 |
| Income (median) | $30,075 | $52,037 |
| Home Value (median) | $165,600 | $210,500 |
| White | 71% | 79% |
| Black | 19% | 11% |
| Asian | 1% | 1% |
| With Kids | 28% | 37% |
| Age (median) | 36 | 41 |
| Rentals | 54% | 19% |
Questions and Answers:
Q: Which is more populated, Lake Worth or Bloomingdale?
A: Lake Worth has a larger population count than Bloomingdale: 37354 compared with 23395 total people.
Q: Do incomes tend to be higher in Lake Worth or in Bloomingdale?
A: Incomes are on average much lower in Lake Worth.
Q: Are homes more expensive in Lake Worth or Bloomingdale?
A: Homes tend to be less expensive in Lake Worth.
Q: Which has a higher percentage of housing rental units?
A: Lake Worth does. The percentage of rentals differs quite a bit: 54% for Lake Worth versus 19% for Bloomingdale.
Somewhat similar in-state cities, towns, and CDPs to Lake Worth may include: Leesburg, Four-Corners, and Panama-City.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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