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Compare Boynton Beach to Sanford
This post compares Boynton Beach, Florida to Sanford, Florida across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Boynton Beach (city) | Sanford (city) |
|---|---|---|
| Population | 74,483 | 57,979 |
| Income (median) | $41,336 | $36,585 |
| Home Value (median) | $164,300 | $113,100 |
| White | 63% | 60% |
| Black | 31% | 26% |
| Asian | 1% | 3% |
| With Kids | 23% | 31% |
| Age (median) | 42 | 33 |
| Rentals | 39% | 47% |
Questions and Answers:
Q: Which is more populated, Boynton Beach or Sanford?
A: Boynton Beach has a larger population count than Sanford: 74483 compared with 57979 total people.
Q: Do incomes tend to be higher in Boynton Beach or in Sanford?
A: Incomes are on average higher in Boynton Beach.
Q: Are homes more expensive in Boynton Beach or Sanford?
A: Homes tend to be more expensive in Boynton Beach.
Q: Which has a higher percentage of housing rental units?
A: Sanford does. The percentage of rentals differs quite a bit: 39% for Boynton Beach versus 47% for Sanford.
Somewhat similar in-state cities, towns, and CDPs to Boynton Beach may include: Deerfield-Beach, Winter-Haven, and Pompano-Beach.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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