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Compare Bloomingdale to Sarasota
This post compares Bloomingdale, Florida to Sarasota, Florida across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Bloomingdale (CDP) | Sarasota (city) |
|---|---|---|
| Population | 23,395 | 55,103 |
| Income (median) | $52,037 | $35,434 |
| Home Value (median) | $210,500 | $215,100 |
| White | 79% | 81% |
| Black | 11% | 13% |
| Asian | 1% | 1% |
| With Kids | 37% | 17% |
| Age (median) | 41 | 47 |
| Rentals | 19% | 44% |
Questions and Answers:
Q: Which is more populated, Bloomingdale or Sarasota?
A: Bloomingdale has a much smaller population count than Sarasota: 23395 compared with 55103 total people.
Q: Do incomes tend to be higher in Bloomingdale or in Sarasota?
A: Incomes are on average much higher in Bloomingdale.
Q: Are homes more expensive in Bloomingdale or Sarasota?
A: Homes tend to be similarly priced in Bloomingdale.
Q: Which has a higher percentage of housing rental units?
A: Sarasota does. The percentage of rentals differs quite a bit: 19% for Bloomingdale versus 44% for Sarasota.
Somewhat similar in-state cities, towns, and CDPs to Bloomingdale may include: Land-O-Lakes, Navarre, and The-Acreage.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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