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Compare Bloomingdale to Sanford
This post compares Bloomingdale, Florida to Sanford, Florida across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Bloomingdale (CDP) | Sanford (city) |
|---|---|---|
| Population | 23,395 | 57,979 |
| Income (median) | $52,037 | $36,585 |
| Home Value (median) | $210,500 | $113,100 |
| White | 79% | 60% |
| Black | 11% | 26% |
| Asian | 1% | 3% |
| With Kids | 37% | 31% |
| Age (median) | 41 | 33 |
| Rentals | 19% | 47% |
Questions and Answers:
Q: Which is more populated, Bloomingdale or Sanford?
A: Bloomingdale has a much smaller population count than Sanford: 23395 compared with 57979 total people.
Q: Do incomes tend to be higher in Bloomingdale or in Sanford?
A: Incomes are on average much higher in Bloomingdale.
Q: Are homes more expensive in Bloomingdale or Sanford?
A: Homes tend to be more expensive in Bloomingdale.
Q: Which has a higher percentage of housing rental units?
A: Sanford does. The percentage of rentals differs quite a bit: 19% for Bloomingdale versus 47% for Sanford.
Somewhat similar in-state cities, towns, and CDPs to Bloomingdale may include: Land-O-Lakes, Navarre, and The-Acreage.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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