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Compare Westminster to American Canyon
This post compares Westminster, California to American Canyon, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Westminster (city) | American Canyon (city) |
|---|---|---|
| Population | 91,785 | 20,341 |
| Income (median) | $43,283 | $54,617 |
| Home Value (median) | $546,200 | $418,600 |
| White | 39% | 38% |
| Black | 0% | 8% |
| Asian | 48% | 35% |
| With Kids | 35% | 50% |
| Age (median) | 41 | 36 |
| Rentals | 47% | 21% |
Questions and Answers:
Q: Which is more populated, Westminster or American Canyon?
A: Westminster has a much larger population count than American Canyon: 91785 compared with 20341 total people.
Q: Do incomes tend to be higher in Westminster or in American Canyon?
A: Incomes are on average lower in Westminster.
Q: Are homes more expensive in Westminster or American Canyon?
A: Homes tend to be more expensive in Westminster.
Q: Which has a higher percentage of housing rental units?
A: Westminster does. The percentage of rentals differs quite a bit: 47% for Westminster versus 21% for American Canyon.
Somewhat similar in-state cities, towns, and CDPs to Westminster may include: South-San-Francisco, Garden-Grove, and San-Gabriel.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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