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Compare Temescal Valley to Rohnert Park
This post compares Temescal Valley, California to Rohnert Park, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Temescal Valley (CDP) | Rohnert Park (city) |
|---|---|---|
| Population | 25,411 | 42,305 |
| Income (median) | $66,775 | $49,835 |
| Home Value (median) | $396,200 | $377,200 |
| White | 65% | 72% |
| Black | 7% | 1% |
| Asian | 8% | 5% |
| With Kids | 39% | 29% |
| Age (median) | 37 | 33 |
| Rentals | 14% | 48% |
Questions and Answers:
Q: Which is more populated, Temescal Valley or Rohnert Park?
A: Temescal Valley has a smaller population count than Rohnert Park: 25411 compared with 42305 total people.
Q: Do incomes tend to be higher in Temescal Valley or in Rohnert Park?
A: Incomes are on average much higher in Temescal Valley.
Q: Are homes more expensive in Temescal Valley or Rohnert Park?
A: Homes tend to be similarly priced in Temescal Valley.
Q: Which has a higher percentage of housing rental units?
A: Rohnert Park does. The percentage of rentals differs quite a bit: 14% for Temescal Valley versus 48% for Rohnert Park.
Somewhat similar in-state cities, towns, and CDPs to Temescal Valley may include: Brentwood, Norco, and Oakley.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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