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Compare Temescal Valley to Manhattan Beach
This post compares Temescal Valley, California to Manhattan Beach, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Temescal Valley (CDP) | Manhattan Beach (city) |
|---|---|---|
| Population | 25,411 | 35,698 |
| Income (median) | $66,775 | $118,119 |
| Home Value (median) | $396,200 | $1,694,900 |
| White | 65% | 79% |
| Black | 7% | 0% |
| Asian | 8% | 10% |
| With Kids | 39% | 32% |
| Age (median) | 37 | 43 |
| Rentals | 14% | 31% |
Questions and Answers:
Q: Which is more populated, Temescal Valley or Manhattan Beach?
A: Temescal Valley has a smaller population count than Manhattan Beach: 25411 compared with 35698 total people.
Q: Do incomes tend to be higher in Temescal Valley or in Manhattan Beach?
A: Incomes are on average much lower in Temescal Valley.
Q: Are homes more expensive in Temescal Valley or Manhattan Beach?
A: Homes tend to be much less expensive in Temescal Valley.
Q: Which has a higher percentage of housing rental units?
A: Manhattan Beach does. The percentage of rentals differs quite a bit: 14% for Temescal Valley versus 31% for Manhattan Beach.
Somewhat similar in-state cities, towns, and CDPs to Temescal Valley may include: Brentwood, Norco, and Oakley.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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