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Compare Temecula to Huntington Park
This post compares Temecula, California to Huntington Park, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Temecula (city) | Huntington Park (city) |
|---|---|---|
| Population | 110,722 | 58,993 |
| Income (median) | $59,886 | $25,808 |
| Home Value (median) | $394,600 | $357,500 |
| White | 69% | 62% |
| Black | 5% | 1% |
| Asian | 9% | 0% |
| With Kids | 45% | 52% |
| Age (median) | 34 | 30 |
| Rentals | 35% | 73% |
Questions and Answers:
Q: Which is more populated, Temecula or Huntington Park?
A: Temecula has a larger population count than Huntington Park: 110722 compared with 58993 total people.
Q: Do incomes tend to be higher in Temecula or in Huntington Park?
A: Incomes are on average much higher in Temecula.
Q: Are homes more expensive in Temecula or Huntington Park?
A: Homes tend to be similarly priced in Temecula.
Q: Which has a higher percentage of housing rental units?
A: Huntington Park does. The percentage of rentals differs quite a bit: 35% for Temecula versus 73% for Huntington Park.
Somewhat similar in-state cities, towns, and CDPs to Temecula may include: Murrieta, Manteca, and Corona.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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