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Compare Selma to Lawndale
This post compares Selma, California to Lawndale, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Selma (city) | Lawndale (city) |
|---|---|---|
| Population | 24,537 | 33,191 |
| Income (median) | $35,716 | $37,317 |
| Home Value (median) | $171,200 | $417,600 |
| White | 78% | 42% |
| Black | 0% | 10% |
| Asian | 4% | 10% |
| With Kids | 54% | 39% |
| Age (median) | 30 | 35 |
| Rentals | 41% | 67% |
Questions and Answers:
Q: Which is more populated, Selma or Lawndale?
A: Selma has a smaller population count than Lawndale: 24537 compared with 33191 total people.
Q: Do incomes tend to be higher in Selma or in Lawndale?
A: Incomes are on average similar in Selma.
Q: Are homes more expensive in Selma or Lawndale?
A: Homes tend to be much less expensive in Selma.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 41% for Selma versus 67% for Lawndale.
Somewhat similar in-state cities, towns, and CDPs to Selma may include: Sanger, Porterville, and Dinuba.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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