Compare-Cities.com
Compare Seal Beach to American Canyon
This post compares Seal Beach, California to American Canyon, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Seal Beach (city) | American Canyon (city) |
|---|---|---|
| Population | 24,510 | 20,341 |
| Income (median) | $76,405 | $54,617 |
| Home Value (median) | $338,100 | $418,600 |
| White | 80% | 38% |
| Black | 1% | 8% |
| Asian | 10% | 35% |
| With Kids | 13% | 50% |
| Age (median) | 58 | 36 |
| Rentals | 24% | 21% |
Questions and Answers:
Q: Which is more populated, Seal Beach or American Canyon?
A: Seal Beach has a similar population count than American Canyon: 24510 compared with 20341 total people.
Q: Do incomes tend to be higher in Seal Beach or in American Canyon?
A: Incomes are on average much higher in Seal Beach.
Q: Are homes more expensive in Seal Beach or American Canyon?
A: Homes tend to be similarly priced in Seal Beach.
Q: Which has a higher percentage of housing rental units?
A: Seal Beach does. The percentage of rentals is quite similar: 24% for Seal Beach versus 21% for American Canyon.
Somewhat similar in-state cities, towns, and CDPs to Seal Beach may include: Palm-Springs, Palm-Desert, and Walnut-Creek.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
City first letter menu:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z