Compare-Cities.com
Compare Santa Monica to Lawndale
This post compares Santa Monica, California to Lawndale, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Santa Monica (city) | Lawndale (city) |
|---|---|---|
| Population | 92,495 | 33,191 |
| Income (median) | $79,865 | $37,317 |
| Home Value (median) | $1,168,500 | $417,600 |
| White | 76% | 42% |
| Black | 4% | 10% |
| Asian | 10% | 10% |
| With Kids | 16% | 39% |
| Age (median) | 40 | 35 |
| Rentals | 72% | 67% |
Questions and Answers:
Q: Which is more populated, Santa Monica or Lawndale?
A: Santa Monica has a larger population count than Lawndale: 92495 compared with 33191 total people.
Q: Do incomes tend to be higher in Santa Monica or in Lawndale?
A: Incomes are on average much higher in Santa Monica.
Q: Are homes more expensive in Santa Monica or Lawndale?
A: Homes tend to be much more expensive in Santa Monica.
Q: Which has a higher percentage of housing rental units?
A: Santa Monica does. The percentage of rentals is quite similar: 72% for Santa Monica versus 67% for Lawndale.
Somewhat similar in-state cities, towns, and CDPs to Santa Monica may include: Santa-Barbara, Monterey, and West-Hollywood.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
City first letter menu:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z