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Compare Santa Clarita to Lawndale
This post compares Santa Clarita, California to Lawndale, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Santa Clarita (city) | Lawndale (city) |
|---|---|---|
| Population | 209,489 | 33,191 |
| Income (median) | $62,546 | $37,317 |
| Home Value (median) | $461,500 | $417,600 |
| White | 70% | 42% |
| Black | 4% | 10% |
| Asian | 10% | 10% |
| With Kids | 39% | 39% |
| Age (median) | 36 | 35 |
| Rentals | 32% | 67% |
Questions and Answers:
Q: Which is more populated, Santa Clarita or Lawndale?
A: Santa Clarita has a much larger population count than Lawndale: 209489 compared with 33191 total people.
Q: Do incomes tend to be higher in Santa Clarita or in Lawndale?
A: Incomes are on average much higher in Santa Clarita.
Q: Are homes more expensive in Santa Clarita or Lawndale?
A: Homes tend to be similarly priced in Santa Clarita.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 32% for Santa Clarita versus 67% for Lawndale.
Somewhat similar in-state cities, towns, and CDPs to Santa Clarita may include: Corona, Temecula, and San-Marcos.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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