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Compare Santa Barbara to Lawndale
This post compares Santa Barbara, California to Lawndale, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Santa Barbara (city) | Lawndale (city) |
|---|---|---|
| Population | 91,443 | 33,191 |
| Income (median) | $49,574 | $37,317 |
| Home Value (median) | $934,500 | $417,600 |
| White | 77% | 42% |
| Black | 1% | 10% |
| Asian | 3% | 10% |
| With Kids | 23% | 39% |
| Age (median) | 37 | 35 |
| Rentals | 59% | 67% |
Questions and Answers:
Q: Which is more populated, Santa Barbara or Lawndale?
A: Santa Barbara has a larger population count than Lawndale: 91443 compared with 33191 total people.
Q: Do incomes tend to be higher in Santa Barbara or in Lawndale?
A: Incomes are on average much higher in Santa Barbara.
Q: Are homes more expensive in Santa Barbara or Lawndale?
A: Homes tend to be much more expensive in Santa Barbara.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals is quite similar: 59% for Santa Barbara versus 67% for Lawndale.
Somewhat similar in-state cities, towns, and CDPs to Santa Barbara may include: Monterey, Costa-Mesa, and Burbank.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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