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Compare San Leandro to Manhattan Beach
This post compares San Leandro, California to Manhattan Beach, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | San Leandro (city) | Manhattan Beach (city) |
|---|---|---|
| Population | 89,910 | 35,698 |
| Income (median) | $50,011 | $118,119 |
| Home Value (median) | $474,500 | $1,694,900 |
| White | 39% | 79% |
| Black | 11% | 0% |
| Asian | 33% | 10% |
| With Kids | 33% | 32% |
| Age (median) | 40 | 43 |
| Rentals | 45% | 31% |
Questions and Answers:
Q: Which is more populated, San Leandro or Manhattan Beach?
A: San Leandro has a larger population count than Manhattan Beach: 89910 compared with 35698 total people.
Q: Do incomes tend to be higher in San Leandro or in Manhattan Beach?
A: Incomes are on average much lower in San Leandro.
Q: Are homes more expensive in San Leandro or Manhattan Beach?
A: Homes tend to be much less expensive in San Leandro.
Q: Which has a higher percentage of housing rental units?
A: San Leandro does. The percentage of rentals differs quite a bit: 45% for San Leandro versus 31% for Manhattan Beach.
Somewhat similar in-state cities, towns, and CDPs to San Leandro may include: Hayward, West-Covina, and Alameda.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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