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Compare San Leandro to Arvin
This post compares San Leandro, California to Arvin, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | San Leandro (city) | Arvin (city) |
|---|---|---|
| Population | 89,910 | 20,826 |
| Income (median) | $50,011 | $21,815 |
| Home Value (median) | $474,500 | $132,300 |
| White | 39% | 87% |
| Black | 11% | 1% |
| Asian | 33% | 0% |
| With Kids | 33% | 67% |
| Age (median) | 40 | 24 |
| Rentals | 45% | 54% |
Questions and Answers:
Q: Which is more populated, San Leandro or Arvin?
A: San Leandro has a much larger population count than Arvin: 89910 compared with 20826 total people.
Q: Do incomes tend to be higher in San Leandro or in Arvin?
A: Incomes are on average much higher in San Leandro.
Q: Are homes more expensive in San Leandro or Arvin?
A: Homes tend to be much more expensive in San Leandro.
Q: Which has a higher percentage of housing rental units?
A: Arvin does. The percentage of rentals differs quite a bit: 45% for San Leandro versus 54% for Arvin.
Somewhat similar in-state cities, towns, and CDPs to San Leandro may include: Hayward, West-Covina, and Alameda.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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