Compare-Cities.com
Compare San Leandro to American Canyon
This post compares San Leandro, California to American Canyon, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | San Leandro (city) | American Canyon (city) |
|---|---|---|
| Population | 89,910 | 20,341 |
| Income (median) | $50,011 | $54,617 |
| Home Value (median) | $474,500 | $418,600 |
| White | 39% | 38% |
| Black | 11% | 8% |
| Asian | 33% | 35% |
| With Kids | 33% | 50% |
| Age (median) | 40 | 36 |
| Rentals | 45% | 21% |
Questions and Answers:
Q: Which is more populated, San Leandro or American Canyon?
A: San Leandro has a much larger population count than American Canyon: 89910 compared with 20341 total people.
Q: Do incomes tend to be higher in San Leandro or in American Canyon?
A: Incomes are on average similar in San Leandro.
Q: Are homes more expensive in San Leandro or American Canyon?
A: Homes tend to be similarly priced in San Leandro.
Q: Which has a higher percentage of housing rental units?
A: San Leandro does. The percentage of rentals differs quite a bit: 45% for San Leandro versus 21% for American Canyon.
Somewhat similar in-state cities, towns, and CDPs to San Leandro may include: Hayward, West-Covina, and Alameda.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
City first letter menu:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z