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Compare San Jose to Lawndale
This post compares San Jose, California to Lawndale, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | San Jose (city) | Lawndale (city) |
|---|---|---|
| Population | 1,023,031 | 33,191 |
| Income (median) | $61,896 | $37,317 |
| Home Value (median) | $714,200 | $417,600 |
| White | 40% | 42% |
| Black | 3% | 10% |
| Asian | 34% | 10% |
| With Kids | 38% | 39% |
| Age (median) | 36 | 35 |
| Rentals | 42% | 67% |
Questions and Answers:
Q: Which is more populated, San Jose or Lawndale?
A: San Jose has a much larger population count than Lawndale: 1023031 compared with 33191 total people.
Q: Do incomes tend to be higher in San Jose or in Lawndale?
A: Incomes are on average much higher in San Jose.
Q: Are homes more expensive in San Jose or Lawndale?
A: Homes tend to be more expensive in San Jose.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 42% for San Jose versus 67% for Lawndale.
Somewhat similar in-state cities, towns, and CDPs to San Jose may include: San-Diego, San-Francisco, and Irvine.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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