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Compare San Jacinto to American Canyon
This post compares San Jacinto, California to American Canyon, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | San Jacinto (city) | American Canyon (city) |
|---|---|---|
| Population | 46,932 | 20,341 |
| Income (median) | $38,897 | $54,617 |
| Home Value (median) | $188,200 | $418,600 |
| White | 66% | 38% |
| Black | 6% | 8% |
| Asian | 3% | 35% |
| With Kids | 46% | 50% |
| Age (median) | 32 | 36 |
| Rentals | 35% | 21% |
Questions and Answers:
Q: Which is more populated, San Jacinto or American Canyon?
A: San Jacinto has a larger population count than American Canyon: 46932 compared with 20341 total people.
Q: Do incomes tend to be higher in San Jacinto or in American Canyon?
A: Incomes are on average lower in San Jacinto.
Q: Are homes more expensive in San Jacinto or American Canyon?
A: Homes tend to be much less expensive in San Jacinto.
Q: Which has a higher percentage of housing rental units?
A: San Jacinto does. The percentage of rentals differs quite a bit: 35% for San Jacinto versus 21% for American Canyon.
Somewhat similar in-state cities, towns, and CDPs to San Jacinto may include: Antelope, Highland, and Patterson.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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