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Compare San Gabriel to American Canyon
This post compares San Gabriel, California to American Canyon, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | San Gabriel (city) | American Canyon (city) |
|---|---|---|
| Population | 40,315 | 20,341 |
| Income (median) | $40,392 | $54,617 |
| Home Value (median) | $628,300 | $418,600 |
| White | 21% | 38% |
| Black | 0% | 8% |
| Asian | 60% | 35% |
| With Kids | 34% | 50% |
| Age (median) | 41 | 36 |
| Rentals | 54% | 21% |
Questions and Answers:
Q: Which is more populated, San Gabriel or American Canyon?
A: San Gabriel has a larger population count than American Canyon: 40315 compared with 20341 total people.
Q: Do incomes tend to be higher in San Gabriel or in American Canyon?
A: Incomes are on average lower in San Gabriel.
Q: Are homes more expensive in San Gabriel or American Canyon?
A: Homes tend to be more expensive in San Gabriel.
Q: Which has a higher percentage of housing rental units?
A: San Gabriel does. The percentage of rentals differs quite a bit: 54% for San Gabriel versus 21% for American Canyon.
Somewhat similar in-state cities, towns, and CDPs to San Gabriel may include: Rosemead, Alhambra, and Daly-City.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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