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Compare San Diego to Lawndale
This post compares San Diego, California to Lawndale, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | San Diego (city) | Lawndale (city) |
|---|---|---|
| Population | 1,390,966 | 33,191 |
| Income (median) | $51,979 | $37,317 |
| Home Value (median) | $523,600 | $417,600 |
| White | 64% | 42% |
| Black | 6% | 10% |
| Asian | 16% | 10% |
| With Kids | 30% | 39% |
| Age (median) | 34 | 35 |
| Rentals | 53% | 67% |
Questions and Answers:
Q: Which is more populated, San Diego or Lawndale?
A: San Diego has a much larger population count than Lawndale: 1390966 compared with 33191 total people.
Q: Do incomes tend to be higher in San Diego or in Lawndale?
A: Incomes are on average much higher in San Diego.
Q: Are homes more expensive in San Diego or Lawndale?
A: Homes tend to be more expensive in San Diego.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 53% for San Diego versus 67% for Lawndale.
Somewhat similar in-state cities, towns, and CDPs to San Diego may include: San-Jose, San-Francisco, and Long-Beach.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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