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Compare San Bernardino to Lawndale
This post compares San Bernardino, California to Lawndale, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
Dimension | San Bernardino (city) | Lawndale (city) |
---|---|---|
Population | 215,252 | 33,191 |
Income (median) | $33,949 | $37,317 |
Home Value (median) | $202,100 | $417,600 |
White | 57% | 42% |
Black | 14% | 10% |
Asian | 4% | 10% |
With Kids | 47% | 39% |
Age (median) | 29 | 35 |
Rentals | 53% | 67% |
Questions and Answers:
Q: Which is more populated, San Bernardino or Lawndale?
A: San Bernardino has a much larger population count than Lawndale: 215252 compared with 33191 total people.
Q: Do incomes tend to be higher in San Bernardino or in Lawndale?
A: Incomes are on average similar in San Bernardino.
Q: Are homes more expensive in San Bernardino or Lawndale?
A: Homes tend to be much less expensive in San Bernardino.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 53% for San Bernardino versus 67% for Lawndale.
Somewhat similar in-state cities, towns, and CDPs to San Bernardino may include: Victorville, North-Highlands, and Barstow.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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