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Compare Rohnert Park to Temescal Valley
This post compares Rohnert Park, California to Temescal Valley, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Rohnert Park (city) | Temescal Valley (CDP) |
|---|---|---|
| Population | 42,305 | 25,411 |
| Income (median) | $49,835 | $66,775 |
| Home Value (median) | $377,200 | $396,200 |
| White | 72% | 65% |
| Black | 1% | 7% |
| Asian | 5% | 8% |
| With Kids | 29% | 39% |
| Age (median) | 33 | 37 |
| Rentals | 48% | 14% |
Questions and Answers:
Q: Which is more populated, Rohnert Park or Temescal Valley?
A: Rohnert Park has a larger population count than Temescal Valley: 42305 compared with 25411 total people.
Q: Do incomes tend to be higher in Rohnert Park or in Temescal Valley?
A: Incomes are on average lower in Rohnert Park.
Q: Are homes more expensive in Rohnert Park or Temescal Valley?
A: Homes tend to be similarly priced in Rohnert Park.
Q: Which has a higher percentage of housing rental units?
A: Rohnert Park does. The percentage of rentals differs quite a bit: 48% for Rohnert Park versus 14% for Temescal Valley.
Somewhat similar in-state cities, towns, and CDPs to Rohnert Park may include: Woodland, Lodi, and Turlock.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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