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Compare Rocklin to Lawndale
This post compares Rocklin, California to Lawndale, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Rocklin (city) | Lawndale (city) |
|---|---|---|
| Population | 61,697 | 33,191 |
| Income (median) | $68,467 | $37,317 |
| Home Value (median) | $421,700 | $417,600 |
| White | 79% | 42% |
| Black | 1% | 10% |
| Asian | 8% | 10% |
| With Kids | 40% | 39% |
| Age (median) | 37 | 35 |
| Rentals | 33% | 67% |
Questions and Answers:
Q: Which is more populated, Rocklin or Lawndale?
A: Rocklin has a larger population count than Lawndale: 61697 compared with 33191 total people.
Q: Do incomes tend to be higher in Rocklin or in Lawndale?
A: Incomes are on average much higher in Rocklin.
Q: Are homes more expensive in Rocklin or Lawndale?
A: Homes tend to be similarly priced in Rocklin.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 33% for Rocklin versus 67% for Lawndale.
Somewhat similar in-state cities, towns, and CDPs to Rocklin may include: Roseville, Rancho-Santa-Margarita, and Moorpark.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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