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Compare Manhattan Beach to San Leandro
This post compares Manhattan Beach, California to San Leandro, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Manhattan Beach (city) | San Leandro (city) |
|---|---|---|
| Population | 35,698 | 89,910 |
| Income (median) | $118,119 | $50,011 |
| Home Value (median) | $1,694,900 | $474,500 |
| White | 79% | 39% |
| Black | 0% | 11% |
| Asian | 10% | 33% |
| With Kids | 32% | 33% |
| Age (median) | 43 | 40 |
| Rentals | 31% | 45% |
Questions and Answers:
Q: Which is more populated, Manhattan Beach or San Leandro?
A: Manhattan Beach has a much smaller population count than San Leandro: 35698 compared with 89910 total people.
Q: Do incomes tend to be higher in Manhattan Beach or in San Leandro?
A: Incomes are on average much higher in Manhattan Beach.
Q: Are homes more expensive in Manhattan Beach or San Leandro?
A: Homes tend to be much more expensive in Manhattan Beach.
Q: Which has a higher percentage of housing rental units?
A: San Leandro does. The percentage of rentals differs quite a bit: 31% for Manhattan Beach versus 45% for San Leandro.
Somewhat similar in-state cities, towns, and CDPs to Manhattan Beach may include: Los-Gatos, San-Carlos, and Lafayette.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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