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Compare Lawndale to Temescal Valley
This post compares Lawndale, California to Temescal Valley, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Lawndale (city) | Temescal Valley (CDP) |
|---|---|---|
| Population | 33,191 | 25,411 |
| Income (median) | $37,317 | $66,775 |
| Home Value (median) | $417,600 | $396,200 |
| White | 42% | 65% |
| Black | 10% | 7% |
| Asian | 10% | 8% |
| With Kids | 39% | 39% |
| Age (median) | 35 | 37 |
| Rentals | 67% | 14% |
Questions and Answers:
Q: Which is more populated, Lawndale or Temescal Valley?
A: Lawndale has a larger population count than Temescal Valley: 33191 compared with 25411 total people.
Q: Do incomes tend to be higher in Lawndale or in Temescal Valley?
A: Incomes are on average much lower in Lawndale.
Q: Are homes more expensive in Lawndale or Temescal Valley?
A: Homes tend to be similarly priced in Lawndale.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 67% for Lawndale versus 14% for Temescal Valley.
Somewhat similar in-state cities, towns, and CDPs to Lawndale may include: San-Pablo, Bellflower, and Seaside.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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