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Compare Lawndale to Santa Monica
This post compares Lawndale, California to Santa Monica, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Lawndale (city) | Santa Monica (city) |
|---|---|---|
| Population | 33,191 | 92,495 |
| Income (median) | $37,317 | $79,865 |
| Home Value (median) | $417,600 | $1,168,500 |
| White | 42% | 76% |
| Black | 10% | 4% |
| Asian | 10% | 10% |
| With Kids | 39% | 16% |
| Age (median) | 35 | 40 |
| Rentals | 67% | 72% |
Questions and Answers:
Q: Which is more populated, Lawndale or Santa Monica?
A: Lawndale has a much smaller population count than Santa Monica: 33191 compared with 92495 total people.
Q: Do incomes tend to be higher in Lawndale or in Santa Monica?
A: Incomes are on average much lower in Lawndale.
Q: Are homes more expensive in Lawndale or Santa Monica?
A: Homes tend to be much less expensive in Lawndale.
Q: Which has a higher percentage of housing rental units?
A: Santa Monica does. The percentage of rentals is quite similar: 67% for Lawndale versus 72% for Santa Monica.
Somewhat similar in-state cities, towns, and CDPs to Lawndale may include: San-Pablo, Bellflower, and Seaside.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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