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Compare Lawndale to Santa Clarita
This post compares Lawndale, California to Santa Clarita, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Lawndale (city) | Santa Clarita (city) |
|---|---|---|
| Population | 33,191 | 209,489 |
| Income (median) | $37,317 | $62,546 |
| Home Value (median) | $417,600 | $461,500 |
| White | 42% | 70% |
| Black | 10% | 4% |
| Asian | 10% | 10% |
| With Kids | 39% | 39% |
| Age (median) | 35 | 36 |
| Rentals | 67% | 32% |
Questions and Answers:
Q: Which is more populated, Lawndale or Santa Clarita?
A: Lawndale has a much smaller population count than Santa Clarita: 33191 compared with 209489 total people.
Q: Do incomes tend to be higher in Lawndale or in Santa Clarita?
A: Incomes are on average much lower in Lawndale.
Q: Are homes more expensive in Lawndale or Santa Clarita?
A: Homes tend to be similarly priced in Lawndale.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 67% for Lawndale versus 32% for Santa Clarita.
Somewhat similar in-state cities, towns, and CDPs to Lawndale may include: San-Pablo, Bellflower, and Seaside.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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