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Compare Lawndale to Dinuba
This post compares Lawndale, California to Dinuba, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Lawndale (city) | Dinuba (city) |
|---|---|---|
| Population | 33,191 | 23,712 |
| Income (median) | $37,317 | $30,873 |
| Home Value (median) | $417,600 | $164,800 |
| White | 42% | 80% |
| Black | 10% | 0% |
| Asian | 10% | 2% |
| With Kids | 39% | 53% |
| Age (median) | 35 | 28 |
| Rentals | 67% | 49% |
Questions and Answers:
Q: Which is more populated, Lawndale or Dinuba?
A: Lawndale has a larger population count than Dinuba: 33191 compared with 23712 total people.
Q: Do incomes tend to be higher in Lawndale or in Dinuba?
A: Incomes are on average higher in Lawndale.
Q: Are homes more expensive in Lawndale or Dinuba?
A: Homes tend to be much more expensive in Lawndale.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 67% for Lawndale versus 49% for Dinuba.
Somewhat similar in-state cities, towns, and CDPs to Lawndale may include: San-Pablo, Bellflower, and Seaside.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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