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Compare Lawndale to Bloomington
This post compares Lawndale, California to Bloomington, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Lawndale (city) | Bloomington (CDP) |
|---|---|---|
| Population | 33,191 | 22,377 |
| Income (median) | $37,317 | $34,044 |
| Home Value (median) | $417,600 | $226,800 |
| White | 42% | 52% |
| Black | 10% | 3% |
| Asian | 10% | 1% |
| With Kids | 39% | 48% |
| Age (median) | 35 | 32 |
| Rentals | 67% | 31% |
Questions and Answers:
Q: Which is more populated, Lawndale or Bloomington?
A: Lawndale has a larger population count than Bloomington: 33191 compared with 22377 total people.
Q: Do incomes tend to be higher in Lawndale or in Bloomington?
A: Incomes are on average similar in Lawndale.
Q: Are homes more expensive in Lawndale or Bloomington?
A: Homes tend to be more expensive in Lawndale.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 67% for Lawndale versus 31% for Bloomington.
Somewhat similar in-state cities, towns, and CDPs to Lawndale may include: San-Pablo, Bellflower, and Seaside.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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