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Compare Lawndale to American Canyon
This post compares Lawndale, California to American Canyon, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Lawndale (city) | American Canyon (city) |
|---|---|---|
| Population | 33,191 | 20,341 |
| Income (median) | $37,317 | $54,617 |
| Home Value (median) | $417,600 | $418,600 |
| White | 42% | 38% |
| Black | 10% | 8% |
| Asian | 10% | 35% |
| With Kids | 39% | 50% |
| Age (median) | 35 | 36 |
| Rentals | 67% | 21% |
Questions and Answers:
Q: Which is more populated, Lawndale or American Canyon?
A: Lawndale has a larger population count than American Canyon: 33191 compared with 20341 total people.
Q: Do incomes tend to be higher in Lawndale or in American Canyon?
A: Incomes are on average much lower in Lawndale.
Q: Are homes more expensive in Lawndale or American Canyon?
A: Homes tend to be similarly priced in Lawndale.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 67% for Lawndale versus 21% for American Canyon.
Somewhat similar in-state cities, towns, and CDPs to Lawndale may include: San-Pablo, Bellflower, and Seaside.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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