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Compare Huntington Beach to American Canyon
This post compares Huntington Beach, California to American Canyon, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Huntington Beach (city) | American Canyon (city) |
|---|---|---|
| Population | 200,415 | 20,341 |
| Income (median) | $63,765 | $54,617 |
| Home Value (median) | $688,700 | $418,600 |
| White | 74% | 38% |
| Black | 1% | 8% |
| Asian | 11% | 35% |
| With Kids | 28% | 50% |
| Age (median) | 41 | 36 |
| Rentals | 41% | 21% |
Questions and Answers:
Q: Which is more populated, Huntington Beach or American Canyon?
A: Huntington Beach has a much larger population count than American Canyon: 200415 compared with 20341 total people.
Q: Do incomes tend to be higher in Huntington Beach or in American Canyon?
A: Incomes are on average higher in Huntington Beach.
Q: Are homes more expensive in Huntington Beach or American Canyon?
A: Homes tend to be more expensive in Huntington Beach.
Q: Which has a higher percentage of housing rental units?
A: Huntington Beach does. The percentage of rentals differs quite a bit: 41% for Huntington Beach versus 21% for American Canyon.
Somewhat similar in-state cities, towns, and CDPs to Huntington Beach may include: Camarillo, Pleasant-Hill, and San-Rafael.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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