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Compare Granite Bay to Manhattan Beach
This post compares Granite Bay, California to Manhattan Beach, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Granite Bay (CDP) | Manhattan Beach (city) |
|---|---|---|
| Population | 22,479 | 35,698 |
| Income (median) | $96,431 | $118,119 |
| Home Value (median) | $697,500 | $1,694,900 |
| White | 84% | 79% |
| Black | 0% | 0% |
| Asian | 7% | 10% |
| With Kids | 35% | 32% |
| Age (median) | 46 | 43 |
| Rentals | 12% | 31% |
Questions and Answers:
Q: Which is more populated, Granite Bay or Manhattan Beach?
A: Granite Bay has a smaller population count than Manhattan Beach: 22479 compared with 35698 total people.
Q: Do incomes tend to be higher in Granite Bay or in Manhattan Beach?
A: Incomes are on average lower in Granite Bay.
Q: Are homes more expensive in Granite Bay or Manhattan Beach?
A: Homes tend to be much less expensive in Granite Bay.
Q: Which has a higher percentage of housing rental units?
A: Manhattan Beach does. The percentage of rentals differs quite a bit: 12% for Granite Bay versus 31% for Manhattan Beach.
Somewhat similar in-state cities, towns, and CDPs to Granite Bay may include: North-Tustin, El-Dorado-Hills, and Agoura-Hills.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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