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Compare Arvin to Rohnert Park
This post compares Arvin, California to Rohnert Park, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Arvin (city) | Rohnert Park (city) |
|---|---|---|
| Population | 20,826 | 42,305 |
| Income (median) | $21,815 | $49,835 |
| Home Value (median) | $132,300 | $377,200 |
| White | 87% | 72% |
| Black | 1% | 1% |
| Asian | 0% | 5% |
| With Kids | 67% | 29% |
| Age (median) | 24 | 33 |
| Rentals | 54% | 48% |
Questions and Answers:
Q: Which is more populated, Arvin or Rohnert Park?
A: Arvin has a much smaller population count than Rohnert Park: 20826 compared with 42305 total people.
Q: Do incomes tend to be higher in Arvin or in Rohnert Park?
A: Incomes are on average much lower in Arvin.
Q: Are homes more expensive in Arvin or Rohnert Park?
A: Homes tend to be much less expensive in Arvin.
Q: Which has a higher percentage of housing rental units?
A: Arvin does. The percentage of rentals is quite similar: 54% for Arvin versus 48% for Rohnert Park.
Somewhat similar in-state cities, towns, and CDPs to Arvin may include: Wasco, Dinuba, and Madera.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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