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Compare Arvin to Manhattan Beach
This post compares Arvin, California to Manhattan Beach, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | Arvin (city) | Manhattan Beach (city) |
|---|---|---|
| Population | 20,826 | 35,698 |
| Income (median) | $21,815 | $118,119 |
| Home Value (median) | $132,300 | $1,694,900 |
| White | 87% | 79% |
| Black | 1% | 0% |
| Asian | 0% | 10% |
| With Kids | 67% | 32% |
| Age (median) | 24 | 43 |
| Rentals | 54% | 31% |
Questions and Answers:
Q: Which is more populated, Arvin or Manhattan Beach?
A: Arvin has a smaller population count than Manhattan Beach: 20826 compared with 35698 total people.
Q: Do incomes tend to be higher in Arvin or in Manhattan Beach?
A: Incomes are on average much lower in Arvin.
Q: Are homes more expensive in Arvin or Manhattan Beach?
A: Homes tend to be much less expensive in Arvin.
Q: Which has a higher percentage of housing rental units?
A: Arvin does. The percentage of rentals differs quite a bit: 54% for Arvin versus 31% for Manhattan Beach.
Somewhat similar in-state cities, towns, and CDPs to Arvin may include: Wasco, Dinuba, and Madera.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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