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Compare American Canyon to Santa Monica
This post compares American Canyon, California to Santa Monica, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | American Canyon (city) | Santa Monica (city) |
|---|---|---|
| Population | 20,341 | 92,495 |
| Income (median) | $54,617 | $79,865 |
| Home Value (median) | $418,600 | $1,168,500 |
| White | 38% | 76% |
| Black | 8% | 4% |
| Asian | 35% | 10% |
| With Kids | 50% | 16% |
| Age (median) | 36 | 40 |
| Rentals | 21% | 72% |
Questions and Answers:
Q: Which is more populated, American Canyon or Santa Monica?
A: American Canyon has a much smaller population count than Santa Monica: 20341 compared with 92495 total people.
Q: Do incomes tend to be higher in American Canyon or in Santa Monica?
A: Incomes are on average much lower in American Canyon.
Q: Are homes more expensive in American Canyon or Santa Monica?
A: Homes tend to be much less expensive in American Canyon.
Q: Which has a higher percentage of housing rental units?
A: Santa Monica does. The percentage of rentals differs quite a bit: 21% for American Canyon versus 72% for Santa Monica.
Somewhat similar in-state cities, towns, and CDPs to American Canyon may include: Vineyard, Eastvale, and Elk-Grove.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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