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Compare American Canyon to San Jacinto
This post compares American Canyon, California to San Jacinto, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | American Canyon (city) | San Jacinto (city) |
|---|---|---|
| Population | 20,341 | 46,932 |
| Income (median) | $54,617 | $38,897 |
| Home Value (median) | $418,600 | $188,200 |
| White | 38% | 66% |
| Black | 8% | 6% |
| Asian | 35% | 3% |
| With Kids | 50% | 46% |
| Age (median) | 36 | 32 |
| Rentals | 21% | 35% |
Questions and Answers:
Q: Which is more populated, American Canyon or San Jacinto?
A: American Canyon has a much smaller population count than San Jacinto: 20341 compared with 46932 total people.
Q: Do incomes tend to be higher in American Canyon or in San Jacinto?
A: Incomes are on average much higher in American Canyon.
Q: Are homes more expensive in American Canyon or San Jacinto?
A: Homes tend to be much more expensive in American Canyon.
Q: Which has a higher percentage of housing rental units?
A: San Jacinto does. The percentage of rentals differs quite a bit: 21% for American Canyon versus 35% for San Jacinto.
Somewhat similar in-state cities, towns, and CDPs to American Canyon may include: Vineyard, Eastvale, and Elk-Grove.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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