Compare-Cities.com
Compare American Canyon to Rowland Heights
This post compares American Canyon, California to Rowland Heights, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | American Canyon (city) | Rowland Heights (CDP) |
|---|---|---|
| Population | 20,341 | 50,572 |
| Income (median) | $54,617 | $42,165 |
| Home Value (median) | $418,600 | $594,400 |
| White | 38% | 24% |
| Black | 8% | 1% |
| Asian | 35% | 61% |
| With Kids | 50% | 32% |
| Age (median) | 36 | 41 |
| Rentals | 21% | 34% |
Questions and Answers:
Q: Which is more populated, American Canyon or Rowland Heights?
A: American Canyon has a much smaller population count than Rowland Heights: 20341 compared with 50572 total people.
Q: Do incomes tend to be higher in American Canyon or in Rowland Heights?
A: Incomes are on average higher in American Canyon.
Q: Are homes more expensive in American Canyon or Rowland Heights?
A: Homes tend to be less expensive in American Canyon.
Q: Which has a higher percentage of housing rental units?
A: Rowland Heights does. The percentage of rentals differs quite a bit: 21% for American Canyon versus 34% for Rowland Heights.
Somewhat similar in-state cities, towns, and CDPs to American Canyon may include: Vineyard, Eastvale, and Elk-Grove.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
City first letter menu:
A B C D E F G H I J K L M N O P Q R S T U V W X Y Z