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Compare American Canyon to Lawndale
This post compares American Canyon, California to Lawndale, California across various dimensions, including population, median income, median age, percentage of housing that is rental, percent of households with kids, and other demographics.
| Dimension | American Canyon (city) | Lawndale (city) |
|---|---|---|
| Population | 20,341 | 33,191 |
| Income (median) | $54,617 | $37,317 |
| Home Value (median) | $418,600 | $417,600 |
| White | 38% | 42% |
| Black | 8% | 10% |
| Asian | 35% | 10% |
| With Kids | 50% | 39% |
| Age (median) | 36 | 35 |
| Rentals | 21% | 67% |
Questions and Answers:
Q: Which is more populated, American Canyon or Lawndale?
A: American Canyon has a smaller population count than Lawndale: 20341 compared with 33191 total people.
Q: Do incomes tend to be higher in American Canyon or in Lawndale?
A: Incomes are on average much higher in American Canyon.
Q: Are homes more expensive in American Canyon or Lawndale?
A: Homes tend to be similarly priced in American Canyon.
Q: Which has a higher percentage of housing rental units?
A: Lawndale does. The percentage of rentals differs quite a bit: 21% for American Canyon versus 67% for Lawndale.
Somewhat similar in-state cities, towns, and CDPs to American Canyon may include: Vineyard, Eastvale, and Elk-Grove.
The statistics and analyses on this page are based on data from the U.S. Census American Community Survey.
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